x^2=((x+1)(x-1))+1

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Solution for x^2=((x+1)(x-1))+1 equation: 



x^2=((x+1)(x-1))+1

We move all terms to the left:

x^2-(((x+1)(x-1))+1)=0

We use the square of the difference formula

x^2+x^2+1=0

We add all the numbers together, and all the variables

2x^2+1=0

a = 2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·2·1
Δ = -8
Delta is less than zero, so there is no solution for the equation

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